2/3x^2-4x+5=0

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Solution for 2/3x^2-4x+5=0 equation: 


x in (-oo:+oo)

(2/3)*x^2-(4*x)+5 = 0

(2/3)*x^2-4*x+5 = 0

2/3*x^2-4*x+5 = 0

DELTA = (-4)^2-(2/3*4*5)

DELTA = 8/3

DELTA > 0

x = ((8/3)^(1/2)+4)/(2/3*2) or x = (4-(8/3)^(1/2))/(2/3*2)

x = 3/4*((8/3)^(1/2)+4) or x = 3/4*(4-(8/3)^(1/2))

x in { 3/4*(4-(8/3)^(1/2)), 3/4*((8/3)^(1/2)+4) }

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